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The power of a converging lens is 10D. If it forms a real image at a distance of 40 cm from the lens, calculate the position of the object. |
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Answer» \(f=\frac{1}{10}=0.1\,m=10\,cm\) \(\frac{1}{40}-\frac{1}{u}=\frac{1}{10}\) \(\frac{1}{40}-\frac{1}{10}=\frac{1}{u}\) \(\frac{1-4}{40}=\frac{1}{u}\) \(\frac{-3}{40}=\frac{1}{u}\) \(u=\frac{-40}{3}\) |
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