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The power of a lens used by short sighted person, is -2D. Find the maximum distance of an object which he can see without spectacles. |
Answer» Power(P)=`1/("Focal length (m)")` Given,P=-2D `therefore` Focal length=`-1/2=0.5mrArrF=-50 cm` Hence, maximum distance of an object, which he can see without spectacles is 50 cm. |
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