The power radiated by a black body A is E_(A) and the maximum energy radiated was at the wavelength lambda_(A).The power radiated by another black body B is E_(B) = NE_(A) and the radiated energy was at the maximum wavelength, (3)/(4)lambda_(A). What is the value of N?

The power radiated by a black body A is E_(A) and the maximum energy r

1.	The power radiated by a black body A is E_(A) and the maximum energy radiated was at the wavelength lambda_(A).The power radiated by another black body B is E_(B) = NE_(A) and the radiated energy was at the maximum wavelength, (3)/(4)lambda_(A). What is the value of N?
Answer» Solution :According to Wien.s displacement law `lambda_("MAX")T="constant for both object A and B"` `lambda_(A)T_(A)=lambda_(B)T_(B)` `"Here"lambda_(B)=(1)/(2)lambda_(A)` `(T_(B))/(T_(A))=(lambda_(A))/(lambda_(B))=(1)/((1)/(2))=2` `T_(B)=2T_(A)` From Stefan - Boltzmann law `(E_(B))/(E_(A))=((T_(B))/(T_(A)))^(4)=(2)^(4)=16=N` Object B has emitted at LOWER wavelength compared to A. So the object B would have emitted more energetic radiation than A.