The power radiated by a black body is P and it radiates maximum energy at wavelength, lamda_(0). If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 3/4lamda_(0), the power radiated by it becomes nP. The value of n is

The power radiated by a black body is P and it radiates maximum energy

1.	The power radiated by a black body is P and it radiates maximum energy at wavelength, lamda_(0). If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 3/4lamda_(0), the power radiated by it becomes nP. The value of n is
Answer» `3/4` `4/3` `(256)/(81)` `(81)/(256)` Solution :From STEFAN - Boltzmann.s law, `P=sigmaAT^(4)""[becausee=1]` `:.PpropT^(4)""[becausesigma" and A equal"]` Now, from Wein.s DISPLACEMENT law, `Tprop(1)/(lamda_(m))` `:.Pprop(1)/(lamda_(m)^(4))` `:.(P_(2))/(P_(1))=((lamdam_(1))/(lamdam_(2)))^(4)=((lamda_(0))/(3/4lamda_(0)))^(4)` `:.(nP)/(P)=((4)/(3))^(4)=(256)/(81)` `:.n=(256)/(81)`