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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56 Find their present ages (in years).1. 20, 35, 452. 16, 28, 363. 8, 20, 284. 8, 14, 18 |
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Answer» Correct Answer - Option 2 : 16, 28, 36 Given: The ratio of present ages of three persons are in the ratio 4 : 7 : 9 8 years ago sum of their ages were = 56 Calculation: Let us take the ratio of ages be 4x, 7x, 9x respectively Ages of the person before 8 years = (4x - 8), (7x - 8), (9x - 8) According to the question ⇒ (4x - 8) + (7x - 8) + (9x - 8) = 56 ⇒ 20x - 24 = 56 ⇒ 20x = 80 ⇒ x = 4 Substituting the values in ratio ⇒ 4 × 4 : 7 × 4 : 9 × 4 = 16 : 28 : 36 ∴ The present ages of 3 persons are 16, 28, 36 |
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