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The present population of a city is 363000. If it increases by 10% every year, then what was the population 2 years ago? |
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Answer» Present Population of city = 363000 Rate of increase in population annually = 10% Let the populations 1 year ago be x. Now, x + 10% of x = 363000 x + 10/100 * x = 363000 x + x/10 = 363000 (10x + x )/10 = 363000 11x/10 = 363000 11x = 363000 x 10 x = 3630000/11 x = 330000 The population 1 year ago will be 330000. The population 2 year ago will be 2 x 330000 = 660000 |
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