1.

The present population of a city is 363000. If it increases by 10% every year,  then what was the population 2 years ago?

Answer»

Present Population of city = 363000

Rate of increase in population annually = 10%

Let the populations 1 year ago be x.

Now,

x + 10% of x = 363000

x + 10/100 * x = 363000

x + x/10 = 363000

(10x + x )/10 = 363000

11x/10 = 363000

11x = 363000 x 10

x = 3630000/11

x = 330000

The population 1 year ago will be 330000.

The population 2 year ago will be  2 x 330000 = 660000



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