1.

The pressure and temperature of 4 dm^(3) of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

Answer»

`2 dm^(3)`
`3 dm^(3)`
`4 dm^(3)`
`8 dm^(3)`

Solution :`(p_(1)V_(1))/( T_(1)) = ( p_(2) V_(2))/( T_(2))`
`( p XX 4)/( T ) = ( 2P xx V_(2))/( 2T)`
`:. V_(2) = 4 dm^(3)`


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