The pressure exerted by 6.0 g of methane gas in a 0.03 m^(3) vessel at 129^(@)C is (Atomic masses : C = 12.01, H = 1.01 and R = 8.314 JK^(-1)mol^(-1))

The pressure exerted by 6.0 g of methane gas in a 0.03 m^(3) vessel at

1.	The pressure exerted by 6.0 g of methane gas in a 0.03 m^(3) vessel at 129^(@)C is (Atomic masses : C = 12.01, H = 1.01 and R = 8.314 JK^(-1)mol^(-1))
Answer» 31684 PA 215216 Pa 13409 Pa 41648 Pa Solution :`P=(NRT)/(V)` `= (6)/(16.02)=(8.314xx402)/(0.03)=41648` Pa