1.

The pressure exerted by 6.0 g of methane gas in a 0.03 m^(3) vessel at 129^(@)C is (Atomic masses : C=12.01, H=1.01 and R=8.314 JK^(-1)mol^(-1))

Answer»

215216 Pa
13409 Pa
41648 Pa
31684 Pa

Solution :MOLAR MASS of `CH_(4)=12.01+4xx1.01`
`=16.05" G "mol^(-1)`
`:. 6" g of "CH_(4)=(6)/(16.05)"mole"`,
`T= 129^(@)C=129+273" K"=402" K"`
PV=nRT
or `P=(nRT)/(V)=(6)/(16.05)xx(8.314xx402)/(0.03)=41648" Pa"`


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