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The pressure exerted by 6.0 g of methane gas in a 0.03 m^(3) vessel at 129^(@)C is (Atomic masses : C=12.01, H=1.01 and R=8.314 JK^(-1)mol^(-1)) |
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Answer» 215216 Pa `=16.05" G "mol^(-1)` `:. 6" g of "CH_(4)=(6)/(16.05)"mole"`, `T= 129^(@)C=129+273" K"=402" K"` PV=nRT or `P=(nRT)/(V)=(6)/(16.05)xx(8.314xx402)/(0.03)=41648" Pa"` |
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