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The pressure exerted by a certain mass of enclosed gas at 300 K is 5 × 104 Pa. What will be the pressure exerted by the gas at 600 K if the volume of the gas is kept constant ? |
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Answer» Here, P ∝ T ∴ \(\frac{P_2}{P_1}\) = \(\frac{T_2}{T_1}\) = \(\frac{600}{300}\) = 2 ∴ P = 2P1 = 2 × 5 × 104 Pa = 105 Pa is the required pressure. |
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