The pressure in a monoatomic gas increases linearly from 4 xx10^5Nm^(-2)to 8 xx 10^5Nm^(-2)when its volume increases from 0.2 m^3to 0.5 m^3. Calculate the following: work done by the gas,

The pressure in a monoatomic gas increases linearly from 4 xx10^5Nm^(-

1.	The pressure in a monoatomic gas increases linearly from 4 xx10^5Nm^(-2)to 8 xx 10^5Nm^(-2)when its volume increases from 0.2 m^3to 0.5 m^3. Calculate the following: work done by the gas,
Answer» SOLUTION :Given that, `P_1= 4 xx 10^5N//m^2, P_2 = 8 xx 10^5 N//m^2 , V_1 = 0.2 m^2, V_2= 0.5 m^3` As PRESSURE increases linearly from `P_1` to `P_2, P-V` graph will be a straight line, as SHOWN in fig. Hence work done = AREA under P-V graph = Area of `Delta ABC + `Area `ACDE ` ` =[(V_2 -V_1)( 1/2P_2 P_1) +p_1] =1/2 (P_1 +P_2 )(V_2 -V_1)`