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The pressure of 20L of a gas kept at 300 K is found to be 2 atoms. If the pressure is increased to 3 atom at the same temperature, what will be the new volume? |
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Answer» According to Boyles law, Pv = a constant Therefore, P1V1 = P2V2 Here, P1 = 2atm V1 = 20L P2 = 3atm V2 =? ∴ 2 × 20 = 3 × V2 Thus, v2 = \(\frac{2\times20}{3}\) = 13.3L |
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