1.

The pressure of 20L of a gas kept at 300 K is found to be 2 atoms. If the pressure is increased to 3 atom at the same temperature, what will be the new volume?

Answer»

According to Boyles law, Pv = a constant 

Therefore, P1V1 = P2V2 

Here, P1 = 2atm V1 = 20L P2 = 3atm V2 =? 

∴ 2 × 20 = 3 × V2

Thus, v2 = \(\frac{2\times20}{3}\) = 13.3L



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