The pressure of a 1 : 4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmoshpere. What would be the partial pressure of dioxygen ?

The pressure of a 1 : 4 mixture of dihydrogen and dioxygen enclosed in

1.	The pressure of a 1 : 4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmoshpere. What would be the partial pressure of dioxygen ?
Answer» `0.8xx10^(5)` ATM `0.008 Nm^(-2)` `8xx10^(4)Nm^(-2)` 0.25 atm SOLUTION :Moles RATIO of `H_(2)` and `O_(2)` is 1 : 4. Hence partial pressure of dioxygen is `THEREFORE` Partial pressure of `O_(2)=` Mole fraction of `O_(2)xx` total pressure of mixture `= (4)/(1+4)xx1=(4)/(5)xx1` atm `= 0.8 atm = 0.8xx105 Nm^(-2)=8xx10^(4)Nm^(-2)`