

InterviewSolution
Saved Bookmarks
1. |
The pressure of a gas in a pipeline is measured with a mercury manometer having one limb open. The difference in the level of the two limbs is 562mm. Calculate the gas pressure in terms of bar. |
Answer» The difference in the level of the two limbs = Pgauge Pgauge = Pabs – Patm Pabs – Patm = 562mm of Hg Pabs – 101.39 = ρgh = 13.6 × 103 × 9.81 × 562/1000 = 75.2 × 103 N/m2 = 75.2KPa Pabs = 101.39 + 75.2 = 176.5kPa ANS: P = 176.5kPa |
|