1.

 The pressure of a gas in a pipeline is measured with a mercury manometer having one limb open. The difference in the level of the two limbs is 562mm. Calculate the gas pressure in terms of bar.

Answer»

The difference in the level of the two limbs = Pgauge

 Pgauge = Pabs – Patm

Pabs – Patm = 562mm of Hg

Pabs – 101.39 = ρgh = 13.6 × 103 × 9.81 × 562/1000 = 75.2 × 103 N/m2 

= 75.2KPa

Pabs = 101.39 + 75.2 = 176.5kPa

 ANS: P = 176.5kPa



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