The pressure of a gas is 80 cm Hg. Now additional 25% of the same gas is introduced in the same vessel. If the process is done at the same temperature, find the final pressure of the gas.

The pressure of a gas is 80 cm Hg. Now additional 25% of the same gas

1.	The pressure of a gas is 80 cm Hg. Now additional 25% of the same gas is introduced in the same vessel. If the process is done at the same temperature, find the final pressure of the gas.
Answer» Solution :INITIAL pressure of gas `(P_(1))=80` cm of Hg , Initial mass of the gas `(m_(1))=m` Final mass of the gas `(P_(2))=?` At constant VOLUME and temperature, According to Boyle.s law `P_(1)/m_(1)=P_(2)/m_(2)` `RARR P_(2)=m_(2)/m_(1)P_(1)=(5m//4)/m times 80=5/4 times 80=100` cm of Hg `therefore P_(2)=100cm` of Hg