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The pressure of two pure liquid A and B which form an ideal solutions are 400 mm Hg and 800 mm Hg respectively at temperature T.A liquid containing 3:1 molar composition pressure can be varied.The solutions is slowly vapourized at temperature T by decreasing the applied pressure starting with a pressure of 760 mm Hg.A pressure gauge (in mm) Hg is connected which give the reading of pressure applied. The reading of pressure Gauge at which only liquid phase exists. |
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Answer» <P>499 `P_("bubble") "point"=X_A P_A^@+X_B^@ P_B^@` `P_("cqycqfyr fcUnq") =X_A P_A^@+X_B^@ P_B^@` =0.75+400+0.25x800=500 mm `y_A=0.75 , " " y_B=0.5` At dew point `1/P_T=y_A/P_A^@+y_B/P_B^@implies1/P_T=0.75/400+0.25/800=(1.5+0.25)/800` `IMPLIES P_T=800/1.75=457.14` mm Hg Below dew point only VAPOUR phase exists |
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