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The primary and secondary coils of a transformer, assumed to be ideal, have 20 and 300 turns of wire, respectively. If the primary voltage is VP = 10 sincot (in volt), what is the maximum voltage in the secondary coil? |
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Answer» Data : Np = 20, Ns = 300, Vp = 10 sin ωt V Vs = \(\cfrac{N_s}{N_p}\) Vp = \(\cfrac{300}{20}\) x 10 sin ωt = 150 sin ωt V This is of the form V0 sin ωt, where V0 is the peak (or maximum) voltage. ∴ The maximum voltage in the secondary coil is 150 V. |
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