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The primary of a transformer has 200 turns and secondary has 1000 turns. The power output from secondary at 1000 V is 9 kW. Calculate primary voltage and heat loss in primary. Take resistance of primary coil `0.2 Omega` and efficiency of transformer = 90%. |
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Answer» Here,`x_(P) = 200, n_(s) = 1000 , E_(s) = 1000 V`, `P = 9 kW = 9000 W` `E_(P) = ?, H = ?, R_(P) = 0.2 Omega, eta = 90%` As `(E_(s))/(E_(P)) = (n_(s))/(n_(P)) = (1000)/(200) = 5` `:. E_(P) = (E_(s))/(5) = (1000)/(5) = 200 V` From `eta = (P_(0))/(P_(i)) , P_(i) = (P_(0))/(n) = 10 kW` `:. I_(P) = (1000)/(200) = 50 A` Energy loss in primary `= I_(P)^(2) xx R_(P) = (50)^(2) xx 0.2 = 500 W` |
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