The principal value of \(sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)isA

1.	The principal value of \(sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)isA. \(\frac{\pi}{6}\)B. \(\frac{-\pi}{6}\)C. \(\frac{5\pi}{6}\)D. \(\frac{7\pi}{6}\)
Answer» Correct Answer is \(\frac{5\pi}{6}\) Let the principle value be given by x Now, let x = \(sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\) ⇒ sec x = \(\frac{-2}{\sqrt{3}}\) ⇒ sec x= - sec( \(\frac{\pi}{6}\)) ( \(\because sec\left(\frac{\pi}{6}\right)=\left(\frac{2}{\sqrt{3}}\right)\) ⇒ sec x=sec( \(\pi-\frac{\pi}{6}\)) ( \(\because -sec(\theta)=sec(\pi-\theta\))) ⇒ x =\(\frac{5\pi}{6}\)

The principal value of \(sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)isA. \(\frac{\pi}{6}\)B. \(\frac{-\pi}{6}\)C. \(\frac{5\pi}{6}\)D. \(\frac{7\pi}{6}\)

Answer»

Correct Answer is \(\frac{5\pi}{6}\)

Let the principle value be given by x

Now, let x = \(sec^{-1}\left(\frac{-2}{\sqrt{3}}\right)\)

⇒ sec x = \(\frac{-2}{\sqrt{3}}\)

⇒ sec x= - sec( \(\frac{\pi}{6}\)) ( \(\because sec\left(\frac{\pi}{6}\right)=\left(\frac{2}{\sqrt{3}}\right)\)

⇒ sec x=sec( \(\pi-\frac{\pi}{6}\)) ( \(\because -sec(\theta)=sec(\pi-\theta\)))

⇒ x =\(\frac{5\pi}{6}\)