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The probability of an event A occurring is 0.5 and B occurring is 0.3. If A and B are mutually exclusive events, then find the probability of (i) P(A ∪ B) (ii) P(A ∩ \(\bar{B}\)) (iii) P(\(\bar{A}\) ∩ B) |
Answer» P(A) = 0.5, P(B) = 0.3 Here A and B are mutually exclusive. (i) P(A ∪ B) = P(A) + P(B) = 0.5 + 0.3 = 0.8 (ii) P(A ∩ B) = P(A) + P(B) – P(A ∪ B) = 0.5 + 0.3 – 0.8 P(A ∩ B) = 0 P(A ∩ \(\bar{B}\)) = P(A) – P(A ∩ B) = 0.5 – 0 = 0.5 (iii) P(\(\bar{A}\) ∩ B) = P(B) – P(A ∩ B) = 0.3 – 0 = 0.3 |
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