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The probability that a man can hit a target is `3//4`. He tries 5 times. The probability that he will hit the target at least three times isA. `(261)/(364)`B. `(371)/((464)`C. `(471)/(502)`D. `(495)/(512)` |
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Answer» Correct Answer - 4 Using binomial distribution `P(x= 3) + P(x=4)+ P(x =5)` So, the required probability is `=.^(5)C_(3)((3)/(4))^(3) ((1)/(4))^(2) +.^(5)C_(4)((3)/(4))^(4)((1)/(4))^(1)+.^(5)C_(5)((3)/(4))^(5)((1)/(4))^(0)` `= (459)/(512)` |
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