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The product fomed when an queous solution of NaBr is electrolyesed in cell having inert electrode are |
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Answer» Na and `Br_(2)` since the electrode potential of `H_(2)O(-0.83 V)` is HIGHER than that of `Na^(+)` (-2.71) therefore `H_(2)O` is reduced in preference to `Na^(+)` ions at anode `2 br^(-)(aq)RARR Br_(2)(g)+2E^(-)` thus `H_(2)` is liberated at the CATHODE `Br_(2)` at the anode and NaOH is left in the solution |
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