1.

The product fomed when an queous solution of NaBr is electrolyesed in cell having inert electrode are

Answer»

Na and `Br_(2)`
Na and `O_(2)`
`H_(2) Br_(2), NaOH`
`H_(2)` and `O_(2)`

Solution :`NaBr overset("ionises")rarrNa^(+)(aq)+Br^(-)(aq)`
since the electrode potential of `H_(2)O(-0.83 V)` is HIGHER than that of `Na^(+)` (-2.71) therefore `H_(2)O` is reduced in preference to `Na^(+)` ions at anode
`2 br^(-)(aq)RARR Br_(2)(g)+2E^(-)`
thus `H_(2)` is liberated at the CATHODE `Br_(2)` at the anode and NaOH is left in the solution


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