The product of two consecutive even numbers is 7568. What is 150% of t

1.	The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?1). 2042). 2613). 3044). 198
Answer» Solution Let EVEN numbers be '2n' and '2n+2'. According to question, $2n\times(2n+2)=7568$. $4n(n+1)=7568$. $n(n+1)=1892$. $n=43$. HENCE, numbers are 86 and 88 respectively. Sum of numbers=86+88. =174. 150% of sum of numbers=$1.5\times174$. $=261$. Hence, Option B is correct.

The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?1). 2042). 2613). 3044). 198

Answer»

Solution

Let EVEN numbers be '2n' and '2n+2'.
According to question,
$2n\times(2n+2)=7568$.
$4n(n+1)=7568$.
$n(n+1)=1892$.
$n=43$.
HENCE, numbers are 86 and 88 respectively.
Sum of numbers=86+88.
=174.
150% of sum of numbers=$1.5\times174$.
$=261$.
Hence, Option B is correct.

Discussion

No Comment Found

Related InterviewSolutions

Which of the following is/are major reforms the Government has introduced in Banking Sector ?(A) Dismantling the complex system of interest rate controls.(B) Eliminating prior approval of the RBI for large loans.(C) Introduction of capital adequacy norms and few other prudential norms1). Only A2). Only B3). Only C4). All A, B and C
The Government recently accepted the report of which committee as per which Foreign investment of 10 per cent or more in a listed company will now be treated as foreign direct investment (FDI)?1). Arvind Mayaram Committee2). Bimal Jalan Committee3). Parthasarthy Shome Committee4). T.K. Bhullar Committee

The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?1). 2042). 2613). 3044). 198

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment