The product of two consecutive numbers is 56. Find ……………A) -

1.	The product of two consecutive numbers is 56. Find ……………A) -8, -7B) 8, -7C) -8, 7D) 8, 7
Answer» Correct option is (A) -8, -7 Let consecutive numbers are x & (x+1). \(\therefore\) x (x+1) = 56 \(\Rightarrow\) \(x^2+x-56=0\) \(\Rightarrow\) \(x^2+8x-7x-56=0\) \(\Rightarrow\) x (x+8) - 7 (x+8) = 0 \(\Rightarrow\) (x-7) (x+8) = 0 \(\Rightarrow\) x = 7 or x = -8 \(\therefore\) Consecutive numbers either -8, -7 or 7, 8. Correct option is A) -8, -7

The product of two consecutive numbers is 56. Find ……………A) -8, -7B) 8, -7C) -8, 7D) 8, 7

Answer»

Correct option is (A) -8, -7

Let consecutive numbers are x & (x+1).

\(\therefore\) x (x+1) = 56

\(\Rightarrow\) \(x^2+x-56=0\)

\(\Rightarrow\) \(x^2+8x-7x-56=0\)

\(\Rightarrow\) x (x+8) - 7 (x+8) = 0

\(\Rightarrow\) (x-7) (x+8) = 0

\(\Rightarrow\) x = 7 or x = -8

\(\therefore\) Consecutive numbers either -8, -7 or 7, 8.

Correct option is A) -8, -7