The products of electrolysis of dilute aqueous solutio of sodium hydride areA. Na at cathode and `H_(2)` at anodeB. `H_(2)` at cathode and `O_(2)` at cathodeC. Na at cathode and `O_(2)` at anodeD. `H_(2)` at both cathode and anode

The products of electrolysis of dilute aqueous solutio of sodium hydri

1.	The products of electrolysis of dilute aqueous solutio of sodium hydride areA. Na at cathode and `H_(2)` at anodeB. `H_(2)` at cathode and `O_(2)` at cathodeC. Na at cathode and `O_(2)` at anodeD. `H_(2)` at both cathode and anode
Answer» Correct Answer - D

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Based on the data given below, the correct order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt A1`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al^(-) lt Br^(-) lt Fe^(2+)`D. `Al^(-) lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

The products of electrolysis of dilute aqueous solutio of sodium hydride areA. Na at cathode and `H_(2)` at anodeB. `H_(2)` at cathode and `O_(2)` at cathodeC. Na at cathode and `O_(2)` at anodeD. `H_(2)` at both cathode and anode

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