1.

The quantity of charge required to obtain one mole of aluminium from Al_(2)O_(3) is_______

Answer»

1F
6F
3F
2F

Solution :* Reaction (Ionization : `Al_(2)O_(3) to AL^(3+) +3O^(2-)`
Reaction forming Al reduction : `Al^(3+) + 3e^(-) to Al`
* So 3 Mole `e^(-) to `1 mole
So, 3F current PRODUCE 1 mole of Al.


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