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The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists. (i) n = 4, l = 2, m_l = -2, m_s = -1/2 (ii) n = 3, l = 2, m_l = 1, m_s = +1/2 (iii) n = 4, l = 1, m_l = 0, m_s = +1/2 (iv) n = 3, l = 2, m_l = -2, m_s = -1/2 (v) n = 3, l = 1, m_l = -1, m_s = +1/2 (vi) n = 4, l = 1, m_l =0 , m_s = +1/2. |
Answer» Solution : `:. (V) < (ii) = (iv) < (III) = (VI) < (i)` `:. 3p < 3d = 3d < 4P = 4p < 4d.` |
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