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The question is in the above attachment with formula​

Answer»

Answer :

✴ Eq. resistance of SERIES :

\bigstar\:\boxed{\tt{R=R_1+R_2}}

✴ Eq. resistance of parallel :

\bigstar\:\boxed{\tt{\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}}}

➳ As per ohm's LAW, CURRENT flow through a CONDUCTOR is directly proportional to the applied potential difference.

Mathematically, V = I × R

✪ Eq. of upper part (series) :

\longrightarrow\tt\:R=R_1+R_2\\ \\ \longrightarrow\tt\:R=10+20\\ \\ \longrightarrow\tt\:R=30\Omega

✪ Eq. of lower part (series) :

\longrightarrow\tt\:R'=R_3+R_4\\ \\ \longrightarrow\tt\:R'=5+25\\ \\ \longrightarrow\tt\:R'=30\Omega

✪ Net eq. of circuit (parallel) :

\longrightarrow\tt\:\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\ \\ \longrightarrow\tt\:\dfrac{1}{R_{eq}}=\dfrac{1}{30}+\dfrac{1}{30}\\ \\ \longrightarrow\tt\:\dfrac{1}{R_{eq}}=\dfrac{2}{30}\\ \\ \longrightarrow\underline{\boxed{\bf{R_{eq}=15\Omega}}}

✪ Current flow :

\longrightarrow\tt\:V=I\times R_{eq}\\ \\ \longrightarrow\tt\:12=I\times 15\\ \\ \longrightarrow\underline{\boxed{\bf{I=0.8A}}}


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