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The r.m.s. velocity of hydrogen is sqrt(7) times the r.m.s. velocity 1.0 g cm^(-3) and that of wate vapours is 0.0006 g cm^(-3), then the volume of water molecules in 1 L of steam at this temperature is |
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Answer» `T(H_(2)) = T(N_(2))` or `(3RT_((H_(2))))/(2) = 7 xx (3RT_((N_(2))))/(28)` or `T_((N_(2))) = 2T_((H_(2)))` `:. T_((N_(2))) gt T_((H_(2)))` |
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