The r.m.s. velocity of hydrogen is sqrt(7) times the r.m.s. velocity of nitrogen. If T is the temperature of the gas,

The r.m.s. velocity of hydrogen is sqrt(7) times the r.m.s. velocity o

1.	The r.m.s. velocity of hydrogen is sqrt(7) times the r.m.s. velocity of nitrogen. If T is the temperature of the gas,
Answer» `T(H_(2))=T(N_(2))` `T(H_(2))=SQRT(7)T(N_(2))` `T(N_(2))=2T(H_(2))` `T(N_(2))=sqrt(7)T(H_(2))` Solution :`u=sqrt((3RT)/(M)),(u(H_(2)))/(u(N_(2)))=sqrt((T(H_(2)))/(M(N_(2)))xx(M(N_(2)))/(T(N_(2))))`, `sqrt(7)=sqrt((T(H_(2)))/(T(N_(2)))xx(28)/(2)),7=(T(H_(2)))/(T(N_(2)))xx14` or `T(N_(2))=2T (H_(2))` i.e., `T(N_(2)) GT T(H_(2))" or "T(H_(2)) lt T(N_(2))`.