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The r.m.s. velocity of hydrogen is `sqrt(7)` times the r.m.s. velocity `1.0 g cm^(-3)` and that of wate vapours is `0.0006 g cm^(-3)`, then the volume of water molecules in 1 L` of steam at this temperature isA. `T(H_(2)) = T(N_(2))`B. `T(H_(2)) gt T(N_(2))`C. `T(N_(2)) gt T(H_(2))`D. `T(H_(2)) = sqrt(7)T(N_(2))` |
Answer» Correct Answer - C `sqrt((3RT_((H_(2))))/(2)) = sqrt(7)sqrt((3RT_((N_(2))))/(28))` or `(3RT_((H_(2))))/(2) = 7 xx (3RT_((N_(2))))/(28)` or `T_((N_(2))) = 2T_((H_(2)))` `:. T_((N_(2))) gt T_((H_(2)))` |
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