The radical halogenation of 2-methyl propane gives two products (CH_(3))_(2)CHCH_(2)X_(("minor")) and (CH_(3))_(3)CX_(("major")). Chlorination givs larger amount of the minor product than the bromination because

The radical halogenation of 2-methyl propane gives two products (CH_(3

1.	The radical halogenation of 2-methyl propane gives two products (CH_(3))_(2)CHCH_(2)X_(("minor")) and (CH_(3))_(3)CX_(("major")). Chlorination givs larger amount of the minor product than the bromination because
Answer» BROMIDE is more reactive than chlorine and is able to attack the less reactive `3^(@)C-H` Brominie atoms are less reactive (more selective) than chlorine and preferentially atack the weaker `3^(@)C-H` bond. The METHYL GROUPS are more HINDERED to attack by the larger bromine atom. Bromination is REVERSIBLE and more stable `3^(@)-` alkyl bromide is formed exlusively. Solution :Chlorine is more reactive, less selective bromine is less reactive, more selective