The radical halogenation of 2 - methyl propane gives two products (CH_(3))_(2)CHCH_(2)X_("(minor)") and (CH_(3))_(3)CX_("(major)"). Chlorination gives larger amount of the minor product than the bromination because

The radical halogenation of 2 - methyl propane gives two products (CH_

1.	The radical halogenation of 2 - methyl propane gives two products (CH_(3))_(2)CHCH_(2)X_("(minor)") and (CH_(3))_(3)CX_("(major)"). Chlorination gives larger amount of the minor product than the bromination because
Answer» Bromine is more REACTIVE than chlorine and is able to attack the less reactive `3^(@)C-H` Bromine ATOMS are less reactive (more selective) than chlorine and preferentially attack the WEAKER `3^(@)C-H` bond. The METHYL groups are more hindered to attack by the larger bromine atom Bromination is reversible and more stable `3^(@)-` alkyl bromide is formed exclusively. Solution :Chlorine is more reactive, less selective Bromine is less reactive, more selective