The radical halogenation of 2-methylpropane gives two products: (CH_(3))_(2)CHCH_(2)X (minor) and (CH_(3))_(3)CX (major) Chlorination gives a larger amount of the minor product than does bromination, why?

The radical halogenation of 2-methylpropane gives two products: (CH_(3

1.	The radical halogenation of 2-methylpropane gives two products: (CH_(3))_(2)CHCH_(2)X (minor) and (CH_(3))_(3)CX (major) Chlorination gives a larger amount of the minor product than does bromination, why?
Answer» Bromine is more reactive than chlorine and is able to ATTACK the LESS reactive `3^(@)C-H` Bromine atoms are less reactive (more selective) than chlorine, and PREFERENTIALLY attack the weaker `3^(@)C-H` bond The methyl groups are more hindered to attack by the LARGER bromine atom. Bromination is reversible and more STABLE `3^(@)-` alkyl bromide is formed exlusively. Answer :B