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The radii of the escribed circles of triangle ABC are r_a, r_{b } and r_c respectively. If r_a+r_c = 3R and r_b +r_c =2Rthen the smallest angle of the triangle is (where R is the circuradius of triangle ABC) |
| Answer» The radii of the escribed circles of triangle ABC are r_a, r_{b } and r_c respectively. If r_a+r_c = 3R and r_b +r_c =2Rthen the smallest angle of the triangle is (where R is the circuradius of triangle ABC) | |