1.

The radii of two planets are respectively R_(1)andR_(2) and their densities are respectively rho_(1)andrho_(2). The ratio of the accelerations due to gravity (g_(1)//g_(2)) at their surfaces is:

Answer»

`g_(1):g_(2) = (rho_(1))/(R_(1)^(2)):(rho_(2))/(R_(2)^(2))`
`g_(1),g_(2)=R_(1)R_(2),rho_(1)rho_(2)`
`g_(1),g_(2)=R_(1)rho_(2):R_(2)rho_(1)`
`g_(1):g_(2)=R_(1)rho_():R_(2)rho_(2)`

SOLUTION :Using `g = 4/3 pi GR rho , (g_(1))/(g_(2)) = (R_(1)rho_(1))/(R_(2)rho_(2))`


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