The radioactive sources A and B of half lives of t hr and 2t hr respectively, initially contain the same number of radioactive atoms. At the end of t hours, their rates of disintegration are in the ratio:

The radioactive sources A and B of half lives of t hr and 2t hr respec

1.	The radioactive sources A and B of half lives of t hr and 2t hr respectively, initially contain the same number of radioactive atoms. At the end of t hours, their rates of disintegration are in the ratio:
Answer» `2sqrt(2) :1` `1 : 8` `sqrt(2) : 1` ln `2 : 1` Solution :`{:(,A=(t_(1//2)=t"HOUR")/(lambda_(1))X "",, B=(t_(t//2)=2t"hour")/(lambda_(2)),),("at " t=0,,,,),("No. of nuclei",""N_(0),,""N_(0),),(,"Nuclei of A left after time "t(t=t_(1//2)),,"Nuclei of B left after time "t,),(,=(N_(0))/(2),,=N_(0)e^(-lambda_(2)t),),(,"Rate of disintegration of A",,=N_(0)e^(-(LN2)/(2 t)t),),(,=lambda_(1)(N_(0))/(2),,=N_(0)e^(ln((1)/(2))^(1//2)),),(,=(ln 2)/(t) (N_(0))/(2),,=(N_(0))/(sqrt(2)),),(,,,"Rate of disintegration of B",),(,,,=lambda_(2)(N_(0))/(sqrt(2))=(ln2)/(2t)(N_(0))/(sqrt(2)),):}` Ratio of rate of disintegration of A &B `=((ln2)/(t)(N_(0))/(2))/((ln2)/(2t)(N_(0))/(sqrt(2)))=(sqrt(2))/(1)`