1.

The radiu8s of `K^(+)` is 133 pm and that of CI is 181 pm. The volumne of the unit cell of KCI expressed in `10^(-22) cm^(3)` is :A. `0.31`B. `1.21`C. `2.48`D. `6.28`

Answer» Correct Answer - C
`r_(K^(+))+r_(CI^(-))=(a)/(2)`
`133+181=(a)/(2)`
a=2(133+181)
a=628pm
or `a=628xx10^(-10)cm`
and
volume =`a^(3)=(6.28xx10^(-8))^(3)cm^(3)`
`=2.4767xx10^(-22) cm^(2)`
`~~2.48xx10^(-22)m^(3)`


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