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The radiu8s of `K^(+)` is 133 pm and that of CI is 181 pm. The volumne of the unit cell of KCI expressed in `10^(-22) cm^(3)` is :A. `0.31`B. `1.21`C. `2.48`D. `6.28` |
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Answer» Correct Answer - C `r_(K^(+))+r_(CI^(-))=(a)/(2)` `133+181=(a)/(2)` a=2(133+181) a=628pm or `a=628xx10^(-10)cm` and volume =`a^(3)=(6.28xx10^(-8))^(3)cm^(3)` `=2.4767xx10^(-22) cm^(2)` `~~2.48xx10^(-22)m^(3)` |
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