1.

The radius of a ball is (5.4 +- 0.2) cm. The percentage error in the volume of the ball is

Answer»

`11%`
`4%`
`7%`
`9%`

SOLUTION :Percentage ERROR in the VOLUME of the ball `= 3(Deltar)/(r)xx 100= 3 xx (0.2)/(5.4) xx 100= (200)/(18) = 11%`


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