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The radius of a circle is increasing at a rate `((dr)/(dt))=alpha` . Find the rate at which its area is increasing when radius is equal to 3 m. |
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Answer» area of cricle (A)`=pir^(2)` `(dA)/(dt)=pi(2r)(dr)/(dt)=2pir((dr)/(dt))=2pir(alpha)` `((dA)/(dt))_(atr=3m)=6pi alpham^(2)//sec`. |
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