Saved Bookmarks
| 1. |
The radius of a circular plate increase at the rate of `0.1` cm per second. At what rate does the area increase when the radius of plate is `5/pi cm`?A. `1 cm^(2)//s`B. `0.1 cm^(2)//s`C. `0.5 cm^(2)//s`D. `2 cm^(2)//s` |
|
Answer» Correct Answer - A Area of disk, `A=pir^(2)` (where r= radius of disk) `(dA)/(dt)=pi(2r(dr)/(dt))=2pir(dr)/(dt)` so `(dA)/(dt)=2pixx5/pixx0.1=1 cm^(2)//s` |
|