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The radius of a circular-shaped park is 40 m. A path of width 7 m. is played around outside the park. Find the area of the circular path. |
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Answer» Given the radius of a park r = 40 m Area of inner circle = πr2 = \(\frac {22}{7} \times 40 \times 40\) = \(\frac{35200}{7}\) = Area of outer circle = πr2 = \(\frac{22}{7} \times 47\times47\) =\(\frac {48,598} {7}\) = 6942.57 sq.m Area of the path = Outer circle area – Inner circle area = 6942.57 – 5028.57 ∴ Area of circular path = 1914 sq.m |
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