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The radius of a conical vessel is 10 cm and its height is 18 cm. It is completely filled with water. The water is pored into another cylindrical vessel with radius 5 cm. Find the height of water in this vessel. |
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Answer» Given, Radius of conical vessel (R) = 10 cm and its height = 18 cm Volume of conical vessel = \(\frac { 1 }{ 3 }\)r2h = \(\frac { 1 }{ 3 }\) × π × (10)2 × 18 = \(\frac { 1 }{ 3 }\) × π × 100 × 18 π × 100 × 6 = 600 π cm3. Let the height of water in cylindrical vessel be H and its radius = 5 cm. Now, according to question. Volume of cylindrical vessel = Volume of water in the conical vessel. πR2H = 600 π π(5)2H = 600 π H = \(\frac { 600\pi }{ 25\pi } \) = 24 cm Hence, height of water in cylindrical vessel = 24 cm |
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