1.

The radius of a cylinder is 8 cm and its height is 10 cm. If cones of radius 3 cm each and 4 cm deep are carved out from both ends of the cylinder, find the new surface area of the remaining solid?1. 300π cm22. 302π cm23. 289π cm24. 298π cm2

Answer» Correct Answer - Option 1 : 300π cm2

Given:

Radius of a cylinder(R) = 8 cm

Height of cylinder = 10 cm

Radius of cone(r) = 3 cm

Height of cone = 4 cm

Concept:

The surface area of the remaining solid will be the sum of curved surface area of the cylinder, curved surface area of the cones, and the remaining area of the two circular faces of the cylinder.

Formula used:

Curved Surface area cylinder = 2πrh

Curved Surface area Cone = πrl

Slant height of cone = √(r2 + h2)

Surface area of remaining circular face of cylinder = π(R2 – r2)

Where ‘R’ is outer radius

And ‘r’ is inner radius

Calculation:

Curved surface area of cylinder = 2πRh

= 2 × π × 8 × 10

= 160π cm2       ------(1)

Slant height of cone = √[(3)2 + (4)2]

= √(25)

= 5cm

∴ CSA of cone on both faces = 2πrl

= 2 × 5 × 3 × π

= 30π cm2      ------(2)

Surface area of both faces of cylinder = 2π(R2 – r2)

= 2π[(8)2 – (3)2]

= 2π(64 – 9)

= 2π × 55

= 110π cm2       ------(3)

Adding (1), (2) and (3);

Surface area of total solid = (Curved surface area of cylinder) + (CSA of cone on both faces) + Surface area of both circular faces of cylinder)

= 160π cm2 + 30π cm2 + 110π cm2

= 300π cm2



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