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The radius of a hemispherical balloon increases from 6 cm to 12 cm as air is being pumped into it. The ratios of the surface areas of the balloon in the two cases is A. 1 : 4 B. 1 : 3 C. 2 : 3 D. 2 : 1 |
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Answer» A. 1 : 4 Radius of hemisphere initially = 6 cm Radius of hemisphere finally = 12 cm Surface area of hemisphere = 2 x π x r2 Thus ratio of the surface areas = (2 x π x 62)/(2 x π x 122) = 1/4 |
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