The radius of a planet is R_1 and asatellite revolve round of in a circle of radius R_2 .The time period of revolution is T. The acceleration due to the gravitation of the planet at its surface is .

The radius of a planet is R_1 and asatellite revolve round of in a cir

1.	The radius of a planet is R_1 and asatellite revolve round of in a circle of radius R_2 .The time period of revolution is T. The acceleration due to the gravitation of the planet at its surface is .
Answer» SOLUTION :Orbital velocity of the satellite `V_0 =SQRT(G^(1)R_2)` where `g^1=g(R_1/R_2)^2` and angular velocity `OMEGA=V_0/R_2=sqrt(g^(1)/(R_2))=sqrt((g(R_1)^2)/(R_2^3))` But time period of revolution `T = (2PI)/omega= 2pi sqrt((R_2^3)/(gR_1^2))` (or) `T^(2)= 4pi^(2) (R_2^3)/(gR_1^2) ` (or ) `g = (4pi^2)/T^2 (R_2^3)/R_1^2`