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The radius of an air bubble is increasing at the rate of 0.5 centimetre per second. At what rate is the volume of the bubble increasing when the radius is 1 centimetre? |
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Answer» We know that a soap bubble will be in sphere shape Consider the radius of soap bubble as r dr/dt = 0.5 cm/s The volume of soap bubble = 4/3 πr3 Here the rate of change of volume = 4 πr2 dr/dt By substituting the values = 4 × 3.14 × 12 × 0.5 We get dV/dt = 6.28 cm3/s |
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