1.

The radius of an air bubble is increasing at the rate of 0.5 centimetre per second. At what rate is the volume of the bubble increasing when the radius is 1 centimetre?

Answer»

We know that a soap bubble will be in sphere shape

Consider the radius of soap bubble as r

dr/dt = 0.5 cm/s

The volume of soap bubble = 4/3 πr3

Here the rate of change of volume = 4 πr2 dr/dt

By substituting the values

= 4 × 3.14 × 12 × 0.5

We get

dV/dt = 6.28 cm3/s



Discussion

No Comment Found