1.

The radius of gyration of a body about an axis passing through its centre of mass is 24 cm. Calculate the radius of gyration of the body about a parallel axis passing through a point at a distance of 7 cm from its center of mass.

Answer»

Solution :`K_(1)=24 cm, r = 7 cm`
`I=I_(G)+Mr^(2) "" I_(G)=MK_(1)^(2), I=MK^(2)`
`therefore MK^(2)= MK_(1)^(2)+Mr^(2)`
`K^(2)=K_(1)^(2)+r^(2)=(24)^(2)+(7)^(2)=576+49=625`
`therefore` RADIUS of gyration ` K = sqrt(625)=25 cm`


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