The radius of gyration of a ring about the tangent perpendicular to it

1.	The radius of gyration of a ring about the tangent perpendicular to its plane is……………
Answer» `(R )/(2)` `sqrt(2)R` `2 R` `(R )/(sqrt(2))` Solution :`I=I_(C)+Md^(2)` `=MR^(2)+MR^(2)` `I=2MR^(2)` `MK^(2)=2MR^(2)` `therefore k=sqrt(2)R`

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