1.

The radius of gyration of a solid cylinder of mass M and radius R about its own axis is

Answer»

`(R)/(sqrt2)`
`(R)/(2)`
`(R)/(SQRT3)`
`(R)/(3)`

Solution :The MOMENT of inertia of a solid CYLINDER of mass M and radius R about its own axis is
`I = (MR^(2))/(2) "" … (i)`
As `I = MK^(2)` (where k is the radius or gyration) `""` … (ii)
From (i) and (ii) , we get
`k^(2) = (R^(2))/(2) or k = (R)/(sqrt2)`


Discussion

No Comment Found